See Flight Planning Manual MRJT 1 Figure 4.5.3.1 and Figure 4.3.1B.

Given: twin jet aeroplane, Zero fuel mass 50000 kg, Landing mass at alternate 52000 kg, Final reserve fuel 2000 kg, Alternate fuel 1000 kg, Flight to destination: Distance 720 NM, True course 030°, W/V 340°/30 kt, Long range cruise, FL 330, Outside air temperature -30°C

Find: Estimated trip fuel and time with simplified flight planning

This is a question unlikely to appear in the exam .... but it is actually quite simple ...

Looking at Fig 4.3.1b .... to find the FUEL, you need a distance, a wind component, an altitude and a landing mass.

The reference to Fig 4.5.3.1 is simply to allow you to obtain a TAS so you can use your wiz wheel to find the wind component - but accuracy here is not too necessary - use 30 x cos 50 = 19 kt headwind component.

Now Fig 4.3.1b

Enter at 720 nm, up to the wind REF LINE, now adjust to 19kt head wind - make a pencil mark - now up to the 330 altitude curve - then across to the LW REF LINE - make a pencil mark.

We need a LW at destination ... Landing mass at alternate 52000 kg + Alternate fuel 1000 kg = 53000 kg – we now need to adjust to 53000kg ... but we have 2 lines offered – either 37000ft (dashed) or 10000ft …. We are at 33000ft… so interpolate (or follow the 37000ft line and then knock off a fraction) … so follow the 37000ft line to the LW condition 53000kg …. Now read the fuel scale – I get 4900 kg … knock off a fraction … 4800 kg.

Now for time … work your way to the temp REF LINE … OAT -30 … so ISA +20 … 1.85 hrs … 1hr 51 mins