B: 70ºS

A: 70ºS                                                                    060ºE

030ºW

      The great circle track from A to B at A is more than 090ºT but less than 180ºT so it   must be 132ºT: it cannot be any of the other three answers offered

      However: Great circle track     = 090º + Conversion angle

                                                      = 090º + (½ x 90º x sin70º)

                                                      = 132º