B: 70ºS
A: 70ºS 060ºE
030ºW
The great circle track from A to B at A is more than 090ºT but less than 180ºT so it must be 132ºT: it cannot be any of the other three answers offered
However: Great circle track = 090º + Conversion angle
= 090º + (½ x 90º x sin70º)
= 132º