This
question is testing your knowledge of maths.
From the
notes
(Thrust
(T) - Drag (D))/ Weight (W) = Sin Gamma
Mathematically
this could be written
T/W – D/W =
Sin Gamma
Practical
example
(8 – 4) /
2= 2
Same as
8/2 – 4/2
= 2
Since at
small angles of climb lift (L) and weight (W) are considered almost equal you
could replace weight with lift, so returning to the mathematical variation of
our formula we now get
T/W –D/L
The next
step is to consider lift and drag as coefficients.
T/W – CD/CL
= Sin Gamma